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for _ in range (int(input())): n,k=map(int,input().split()) a=list(map(int,input().split())) count=0 for i in a: if(i+k)%7==0: count+=1 ... In this video, we solve the Too Many Items He's not just a rocket scientist… He's the Rank 1 coder on LeetCode — solving over 3600 Compute the difference between maximum and minimum values efficiently using array traversal and comparisons. A classic ... Minimize the usage of resources or operations by analyzing constraints and choosing the most optimal sequence of actions.
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